Python制作简单的剪刀石头布游戏

关于程序相关的

您可以反复玩游戏，直到选择停止为止。 该程序跟踪获胜情况。 大小写无关紧要（即ROCK与Rock相同）。 如果您输入的内容无效，程序会一直提示您，直到您输入有效的内容。

对项目进行编码的步骤：

1. 创建一个简单的单轮游戏版本，我们不执行正确的输入。 如果输入了无效的内容，则添加while循环可重新提示用户输入选择。 使用while循环让用户反复播放，并使用变量来跟踪得分。

程序代码

import random

input("Welcome to Rock, Paper, Scissors! Press Enter to start.")
print()
user_wins = 0
computer_wins = 0

choices = ["rock", "paper", "scissors"]

while True:
 random_index = random.randint(0,2)
 cpu_choice = choices[random_index]

 user_choice = input("Rock, Paper, or Scissors? ").lower()
 while user_choice not in choices:
  user_choice = input("That is not a valid choice. Please try again: ").lower()
 
 print()
 print("Your choice:", user_choice)
 print("Computer's choice:", cpu_choice)
 print()

 if user_choice == 'rock':
  if cpu_choice == 'rock':
   print("It's a tie!")
  elif cpu_choice == 'scissors':
   print("You win!")
   user_wins+=1
  elif cpu_choice == 'paper':
   print("You lose!")
   computer_wins+=1
 elif user_choice == 'paper':
  if cpu_choice == 'paper':
   print("It's a tie!")
  elif cpu_choice == 'rock':
   print("You win!")
   user_wins+=1
  elif cpu_choice == 'scissors':
   print("You lose!")
   computer_wins+=1
 elif user_choice == 'scissors':
  if cpu_choice == 'scissors':
   print("It's a tie!")
  elif cpu_choice == 'paper':
   print("You win!")
   user_wins+=1
  elif cpu_choice == 'rock':
   print("You lose!")
   computer_wins+=1

 print()
 print("You have "+str(user_wins)+" wins")
 print("The computer has "+str(computer_wins)+" wins")
 print()

 repeat = input("Play again? (Y/N) ").lower()
 while repeat not in ['y', 'n']:
  repeat = input("That is not a valid choice. Please try again: ").lower()
 
 if repeat == 'n':
  break

 print("\n----------------------------\n")

运行效果：

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