go语言中fallthrough的用法说明

fallthrough：Go里面switch默认相当于每个case最后带有break，匹配成功后不会自动向下执行其他case，而是跳出整个switch, 但是可以使用fallthrough强制执行后面的case代码。

示例程序1：

switch {
    case false:
        fmt.Println("The integer was <= 4")
        fallthrough
    case true:
        fmt.Println("The integer was <= 5")
        fallthrough
    case false:
        fmt.Println("The integer was <= 6")
        fallthrough
    case true:
        fmt.Println("The integer was <= 7")
        fallthrough
    case false:
        fmt.Println("The integer was <= 8")
    default:
        fmt.Println("default case")
    }

输出结果：

The integer was <= 5

The integer was <= 6

The integer was <= 7

The integer was <= 8

问题：是否在switch最后一个分支使用fallthrough？？？

有错误提示，显示：cannot fallthrough final case in switch

fallthrough不能用在switch的最后一个分支。

示例程序2：

上述示例是true、false常量进行分支判断，看如下变量示例。

s := "abcd"
    switch s[1] {
    case 'a':
        fmt.Println("The integer was <= 4")
        fallthrough
    case 'b':
        fmt.Println("The integer was <= 5")
        fallthrough
    case 'c':
        fmt.Println("The integer was <= 6")
    default:
        fmt.Println("default case")
    }

输出结果如下：

The integer was <= 5

The integer was <= 6

更改为：

s := "abcd"
    switch s[3] {
    case 'a':
        fmt.Println("The integer was <= 4")
        fallthrough
    case 'b':
        fmt.Println("The integer was <= 5")
        fallthrough
    case 'c':
        fmt.Println("The integer was <= 6")
    default:
        fmt.Println("default case")
    }

输出：

default case

总结：

switch分支中使用变量进行判断的时，fallthrough正确的分支开始其作用。

补充：【踩坑】golang的fallthrough大坑

加了fallthrough后，会直接运行【紧跟的后一个】case或default语句，不论条件是否满足都会执行，后面的条件并不会再判断了，?

以上为个人经验，希望能给大家一个参考，也希望大家多多支持。如有错误或未考虑完全的地方，望不吝赐教。