jquery $.post方法不执行怎么办

jquery $.post方法不执行的解决方法：

关于JQuery的post回调函数不执行问题

前端的post回调函数就是不执行, 设置完断点debug还是直接跳过不执行

错误演示 :

后台代码

@RequestMapping(value = "login")
public void CheckUserAccount(@RequestParam("account")String account, HttpServletResponse response) throws IOException{
JSONObject json_account = JSONObject.fromObject(account);
int username = (Integer)json_account.get("username");
String password = json_account.getString("password");
logger.info("username = " + username + " password = " + password);
int status;
status = checkUserAccountService.IsCorrect(username, password);
Map<String, Object> result = new HashMap<String, Object>();
Map<String, String> info_json = new HashMap<String, String>();
if(status == 1){
info_json.put("status", "success");
}else if(status == 0){
info_json.put("status", "errorpassword");
}else{
info_json.put("status", "noexitaccount");
}
result.put("info", info_json);
JSONObject json_object = JSONObject.fromObject(result);
response.setContentType("text/json; charset=utf-8");
response.setHeader("Cache-Control", "no-cache");
PrintWriter out = response.getWriter();
out.print(result);
out.flush();
out.close();
logger.info("验证结果是" + ((Map<String, String>)(result.get("info"))).get("status"));

重点的一句是:

response.setContentType("text/json; charset=utf-8");

此处设置返回的数据为json数据, 但是out.print(result);这里输出的是一个Map, so 前端识别不出任何数据, 结果回调函数直接跳过不执行(因为回调函数只执行json数据)

正确示范 :

改成: out.print(JSONObject.fromObject(result));

就可以了。